Cheryl Burke: Emmitt Smith Isn’t Young Anymore, He Needs to Work on “Everything” on DWTS All-Stars
Emmitt Smith andCheryl Burke had the top score on the premiere of Dancing With the StarsAll-Stars. Then they disappeared into the middle of the pack. Last week, they had something of a comeback with their Guilty Pleasures Samba. They're still entering Country Week 6 with scores toward the middle of the pack — because Week 5’s Team Gangnam Style was scored lower than Team Call Me Maybe (too bad there's no extra point for sex appeal) — but Cheryl talked to TV Guide about their hope to improve for the rest of the competition.
“I think now you'll really be able to see that, since we've gotten a few weeks to settle into the rhythm of the show,” Cheryl said. They have the Foxtrot tonight, which Cheryl said will be “very cute” and soft and show a different side to Emmitt.
Emmitt and Cheryl are the only returning championship team — they won together on Season 3 in 2006 — but so much time has gone by, and the show has changed so much, that Cheryl doesn’t think it gives them advantage. Emmitt is now 43 and Cheryl is 28. Asked what Emmitt still needs to work on, Cheryl answered, “Everything. He's competing against Olympians and almost everybody else is younger than him. We're not young anymore! [Laughs] I think we need to show maturity in our dancing and not repeat something we've already done.”
The only other All-Stars older than Emmitt are Pamela Anderson (who was eliminated on Week 1) at 45 and Kirstie Alley at 61. Kirstie is out there doing cartwheels, but you could argue Emmitt is the stronger technical dancer. He’s got a good mix of entertainment value, like Kirstie, and fancy footwork, like Apolo Ohno. Kirstie is also back with her original partner in Maksim Chmerkovskiy, but they didn’t win the first time. Do you think there’s more pressure on Emmitt and Cheryl to be even better than they were when they won the first time?
Catch a new episode of Dancing With the Stars Season 15: All-Stars on Monday, October 29 at 8 p.m. onABC.