Crazy Pretty Little Liars Superfans Threaten Janel Parrish Over “A” Identity
March 28 at 11:16AM EDT by
Molly Friedman
The cast and crew of Pretty Little Liars had to deal with a lot of fan emotions after finally revealing the identity of “A” on the Season 2 finale (Season 2, Episode 25: “UnmAsked”). But it seems that the most personal bursts of outrage, anger, and mystification were directed at “A” herself, Janel Parrish (Mona Vanderwall).
Janel told Z100’s Elvis...
Pretty Little Liars: All of "A"'s Messages From Season 2
March 27 at 04:24PM EDT by
Rebecca Martin
Now that we know "A" is Mona (Janel Parrish) on Pretty Little Liars, revisiting all of the creepy, threatening, and downright cruel messages she sent the girls is more fun than ever.
In that spirit, here are all of the messages "A" left the girls during the Season 2 winter season. You can see what Mona had to say for herself during the Season 2 summer season here.
From Season 2, Episode 13:...
Was Mona's "A" Plan Flawed? Pretty Little Liars Showrunner Says Yes
March 26 at 03:15PM EDT by
Rebecca Martin
Mona Vanderwaal (Janel Parrish), better known as "A", seemed to have near omniscient powers on Pretty Little Liars. However, according to PLL showrunner Marlene King, even the ever-present "A" isn't a flawless mastermind.
An observant fan pointed out via Twitter that, "Mona's motive didn't make sense b/c her being 'A' is the cause for them being friends again."
For those who have somehow...
Mona Is "A," Black Swan Mystery & Virgins: Pretty Little Liars Week in Review 3/23
March 23 at 04:24PM EDT by
Maria Mercedes Lara
- Here’s the big news: We finally found out who “A” is: Mona!
- Even though it was a little unclear during the episode what with Mona’s references to “the ‘A’ team” (Mr. T?) and the woman in red who visited her at the mental hospital, showrunner Marlene King says that Mona really is “A,” not a fake out.
- Now, onto the new mysteries:...
Bone-Chilling Pics: "A's" Disturbing Lair on Pretty Little Liars (PHOTOS)
March 21 at 11:29AM EDT by
Alissa Kombert
